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Export Exif files from jpeg using shell script
# #!/bin/sh is called shebang
# ref: https://en.wikipedia.org/wiki/Shebang_(Unix)
# #!/usr/bin/env bash means looking into the path and call the first bash found in the path
# ref: https://unix.stackexchange.com/questions/29608/why-is-it-better-to-use-usr-bin-env-name-instead-of-path-to-name-as-my
# bash script if or
# ref: https://stackoverflow.com/questions/3826425/how-to-represent-multiple-conditions-in-a-shell-if-statement
# check file extension
# ref: https://stackoverflow.com/questions/407184/how-to-check-the-extension-of-a-filename-in-a-bash-script
# check file exist
# ref: https://linuxize.com/post/bash-check-if-file-exists/
# shell parameter expansion (eg. remove string pattern)
# ref: http://www.gnu.org/software/bash/manual/html_node/Shell-Parameter-Expansion.html
# ref: https://stackoverflow.com/questions/965053/extract-filename-and-extension-in-bash
# dependency: exiftool install
# tested in OSX 10.12.6 terminal shell
#!/usr/bin/env bash
for FILE in *.*;
do
filename=$(basename -- "$FILE");
extension="${filename##*.}";
filename="${filename%.*}"
# echo $filename.txt
# check exist
if test -f "$FILE"; then
# echo "$FILE exist";
if [[ $FILE == *.JPG || $FILE == *.jpg ]]; then
# echo "$FILE is jpg";
exiftool $FILE > $filename.txt;
fi
fi
done;
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