返回列表内数值的平方和

pythonic

# 方法1
def square_sum(numbers):
    return sum(x**2 for x in numbers)

# 方法2
def square_sum2(numbers):
    return sum(map(lambda x: x**2, numbers))

# 方法3
def square_sum(numbers):
 res = 0
  for num in numbers:
    res = res + num*num
  return res