Fizz Buzz implementation in Coffeescript

fizzbuzz.coffee

rules = [ 
  { divisor: 3, word: "fizz" }
  { divisor: 5, word: "buzz" }
]
 
fizzBuzz = (n) -> 
  say = ""
  say += i.word for i in rules when n % i.divisor is 0
  say || n

console.log fizzBuzz i for i in [1..100] 

Although this can be written idiomatically as the one-liner:

console.log i for i in [1..100].map (n) -> s = (s || "") + w for [d,w] in [[3,"fizz"],[5,"buzz"]] when n%d is 0; s || n

The multi-line code is far more readable, and thus preferable if you are not trying to communicate over twitter.