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Determine the Bandwidth through ALB
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use IisLogs | |
go | |
/****************************************************************** | |
AWS ALB DIMENSION: Mbps per Hour | |
******************************************************************/ | |
declare @dateStart varchar(10) = '2018-07-18', | |
@dateEnd varchar(10) = '2018-07-19', | |
@includeAll bit = 0, | |
@intervalInSeconds int = 1 | |
create table #data | |
( | |
[date] date, | |
[time] time, | |
[avg-in-bits-per-second-per-hour] decimal | |
) | |
insert into #data | |
select [date], [time], sum([sum-in-bits-per-second]) / 3600 [avg-bits-per-second-per-hour] | |
from ( | |
select convert(date, EntryTime) [date] | |
,format(datepart(hour, EntryTime), '0#') + ':00:00' [time] | |
,sum(convert(decimal, csBytes + scBytes) * 8) [sum-in-bits-per-second] | |
from dbo.IisLog | |
where (EntryTime >= @dateStart and EntryTime < @dateEnd) | |
or @includeAll = 1 | |
group by convert(date, EntryTime), | |
datepart(hour, EntryTime), | |
datepart(minute, EntryTime), | |
datepart(second, EntryTime) / @intervalInSeconds | |
) f | |
group by [date], [time] | |
-- 2327838.72 = 2.22 Mbps | |
select [date], [time], [avg-in-bits-per-second-per-hour], | |
convert(decimal(4,2), ([avg-in-bits-per-second-per-hour] / 2327838.72)) [lcus] | |
from #data | |
order by [date], [time] | |
select avg(convert(decimal(4,2), ([avg-in-bits-per-second-per-hour] / 2327838.72))) [avg-lcus] | |
from #data | |
--drop table #data; |
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