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@smc77
Created October 28, 2011 03:14
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Logistic Regression with Gradient Descent
num.iterations <- 1000
# Download South African heart disease data
sa.heart <- read.table("http://www-stat.stanford.edu/~tibs/ElemStatLearn/datasets/SAheart.data", sep=",",head=T,row.names=1)
x <- sa.heart[,c("age", "ldl")]
y <- sa.heart$chd
plot(x, pch=21, bg=c("red","green")[factor(y)])
# Function to standardize input values
zscore <- function(x, mean.val=NA) {
if(is.matrix(x)) return(apply(x, 2, zscore, mean.val=mean.val))
if(is.data.frame(x)) return(data.frame(apply(x, 2, zscore, mean.val=mean.val)))
if(is.na(mean.val)) mean.val <- mean(x)
sd.val <- sd(x)
if(all(sd.val == 0)) return(x) # if all the values are the same
(x - mean.val) / sd.val
}
# Standardize the features
x.scaled <- zscore(x)
# Gradient descent function
grad <- function(x, y, theta) {
gradient <- (1 / nrow(y)) * (t(x) %*% (1/(1 + exp(-x %*% t(theta))) - y))
return(t(gradient))
}
gradient.descent <- function(x, y, alpha=0.1, num.iterations=500, threshold=1e-5, output.path=FALSE) {
# Add x_0 = 1 as the first column
m <- if(is.vector(x)) length(x) else nrow(x)
if(is.vector(x) || (!all(x[,1] == 1))) x <- cbind(rep(1, m), x)
if(is.vector(y)) y <- matrix(y)
x <- apply(x, 2, as.numeric)
num.features <- ncol(x)
# Initialize the parameters
theta <- matrix(rep(0, num.features), nrow=1)
# Look at the values over each iteration
theta.path <- theta
for (i in 1:num.iterations) {
theta <- theta - alpha * grad(x, y, theta)
if(all(is.na(theta))) break
theta.path <- rbind(theta.path, theta)
if(i > 2) if(all(abs(theta - theta.path[i-1,]) < threshold)) break
}
if(output.path) return(theta.path) else return(theta.path[nrow(theta.path),])
}
unscaled.theta <- gradient.descent(x=x, y=y, num.iterations=num.iterations, output.path=TRUE)
scaled.theta <- gradient.descent(x=x.scaled, y=y, num.iterations=num.iterations, output.path=TRUE)
summary(glm(chd ~ age + ldl, family = binomial, data=sa.heart))
qplot(1:(nrow(scaled.theta)), scaled.theta[,1], geom=c("line"), xlab="iteration", ylab="theta_1")
qplot(1:(nrow(scaled.theta)), scaled.theta[,2], geom=c("line"), xlab="iteration", ylab="theta_2")
# Look at output for various different alpha values
vary.alpha <- lapply(c(1e-12, 1e-9, 1e-7, 1e-3, 0.1, 0.9), function(alpha) gradient.descent(x=x.scaled, y=y, alpha=alpha, num.iterations=num.iterations, output.path=TRUE))
par(mfrow = c(2, 3))
for (j in 1:6) {
plot(vary.alpha[[j]][,2], ylab="area (alpha=1e-9)", xlab="iteration", type="l")
}
@bingtangben
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Help me a lot! Thanks~~

@chintanpanchamia
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Thanks!

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