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Last active December 21, 2015 00:39
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How to make sure the SenseApi returns a sensor ID for your own device.
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gistfile1.java
try {
String deviceUuid = SenseApi.getDefaultDeviceUuid(this);
SenseApi.getSensorId(this, "name", null, null, deviceUuid);
} catch (IOException e) {
// TODO: Handle exception when connection failed
} catch (JSONException e) {
// TODO: Handle exception when response was unparsable
}
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