-
-
Save snoyberg/8888998 to your computer and use it in GitHub Desktop.
{-# LANGUAGE RankNTypes #-} | |
import Debug.Trace | |
import Control.Applicative | |
import Control.Lens (view, from, zoom, iso, Iso') | |
import Control.Monad.State.Strict (evalState) | |
import Pipes | |
import Pipes.Core as Pc | |
import qualified Pipes.Parse as Pp | |
import qualified Pipes.Prelude as P | |
newtype A = A Int | |
deriving Show | |
newtype B = B Int | |
deriving Show | |
atob (A i) = traceShow ("atob", i) (B i) | |
btoa (B i) = traceShow ("btoa", i) (A i) | |
ab :: Iso' A B | |
ab = iso atob btoa | |
piso :: Monad m => Iso' a b -> Iso' (Producer a m r) (Producer b m r) | |
piso i = iso (P.map (view i) <-<) (>-> P.map (view $ from i)) | |
main :: IO () | |
main = do | |
let src = P.map A <-< each [1..10] | |
let parser = (,,,) <$> zoom (piso ab) Pp.peek | |
<*> zoom (Pp.splitAt 3) Pp.drawAll | |
<*> zoom (Pp.splitAt 3 . piso ab) Pp.drawAll | |
<*> Pp.drawAll | |
let res = evalState parser src | |
print res |
("atob",1) | |
("btoa",1) | |
("atob",2) | |
("btoa",2) | |
("atob",3) | |
("btoa",3) | |
("atob",4) | |
("btoa",4) | |
("atob",4) | |
("atob",5) | |
("btoa",5) | |
("atob",5) | |
("atob",6) | |
("btoa",6) | |
("atob",6) | |
("atob",7) | |
("btoa",7) | |
("atob",8) | |
("btoa",8) | |
("atob",9) | |
("btoa",9) | |
("atob",10) | |
("btoa",10) | |
(Just (B 1),[A 1,A 2,A 3],[B 4,B 5,B 6],[A 7,A 8,A 9,A 10]) |
Ok I think I understand, zoom (piso ab) Pp.peek
is being applied to the entire stream. You need to delimit it to only the first element if that is all you want it to effect. So the parser:
let parser = (,,,) <$> zoom (Pp.splitAt 1 . piso ab) Pp.peek
<*> zoom (Pp.splitAt 3) Pp.drawAll
<*> zoom (Pp.splitAt 3 . piso ab) Pp.drawAll
<*> Pp.drawAll
results in:
("atob",1)
("btoa",1)
("atob",4)
("atob",5)
("atob",6)
(Just (B 1),[A 1,A 2,A 3],[B 4,B 5,B 6],[A 7,A 8,A 9,A 10])
The fmap solution looks a little bit better since take a round trip from A to B to A is pointless in the case of an isomorphism. Off the top of my head I am unsure if this should be the default behavior of Pp.peek.
That's true for this specific example. But it's not generally true. Consider if, instead of a one-to-one isomorphism like we have here, the incoming stream was UTF8-encoded bytes, and you needed to peek at the first character. Peeking at the first byte (or equivalently using splitAt 1
) would be insufficient. And more specifically, the reason I'm looking at this is to understand pipes-parse's ability to handle leftover preserving.
For a slightly more realistic example, I was playing with the following in conduit: https://gist.github.com/snoyberg/8888288.
Sure this does not work at times when you do not have an isomorphism for the type your are streaming.
The basic idea is that I have an isomorphism, and I'd like to map all input values to convert from type A to type B.
This sentence in your stackoverflow question is where I, I would bet the same is true for J. Abrahamson, made the assumption that A is isomorphic to B in your problem case.
In the cases you care about it is not an isomorphism of the types you are streaming but from isomorphism between two streams. In which case it seems like you need a different approach then the one taken here or on stackoverflow(http://stackoverflow.com/a/21650705/128583).
Chaning the parser to:
results in what I would expect the output to be:
I have not yet used the new pipes-parse api in depth yet however so I do not have insight into why this is the case.