A very simple min and max example in C

min_max.c

#include <stdio.h>

int main(void) {
	int data[] = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
	
	int i = 0;
	int max = data[0];
	int min = data[0];
	
	// Obtain the size of the array by obtaining the number of bytes of the array divided by the size of the first element
	// e.g. 4 bytes for an int would mean the size of the array is 4 * 10 = 40, then divided by the size of an int i.e. 4 is 40 / 4 therefore 10 items
	int size = sizeof(data) / sizeof(data[0]);

	// I have been told it's best to declare i outside of the loop in old versions of C, though in new 'int i = 0' is fine
	for (i = 1; i < size; i++) {
	  	// Assume the new maximum
		if (data[i] > max) {
			max = data[i];
		}
  
    		// Assume the new minimum
		if (data[i] < min) {
			min = data[i];
		}
	}

  	// Print to the console
	printf("%i\n", max);
	printf("%i\n", min);

	return 0;
}