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SECCON CTF quals 2013 | Cryptanalysis (Crypto 300pt)
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a = 1234577 | |
b = 3213242 | |
M = 7654319 | |
def add(A,B): | |
if A==(0,0): return B | |
if B==(0,0): return A | |
x1,y1 = A | |
x2,y2 = B | |
if A!=B: | |
p = (y2-y1)*pow(x2-x1,M-2,M) | |
else: | |
p = (3*x1*x1+a)*pow(2*y1,M-2,M) | |
x3 = p*p-x1-x2 | |
y3 = p*(x1-x3)-y1 | |
return (x3%M,y3%M) | |
base = (5234568, 2287747) | |
pub = (2366653, 1424308) | |
crypt = [(5081741, 6744615), (610619, 6218)] | |
X = (0,0) | |
for i in range(M): | |
if X==pub: | |
secret = i | |
print "secret:" + str(secret) | |
break | |
X = add(X, base) | |
print i | |
#secret = 1584718 | |
tmp =(0,0) | |
for i in range(1584718): | |
tmp = add(tmp,crypt[0]) | |
plain = add(crypt[1], (tmp[0],tmp[1]*-1)) | |
print plain | |
# 2171002 + 3549912 = 5720914 |
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# filename: solver.sage | |
a = 1234577 | |
b = 3213242 | |
M = 7654319 | |
E = EllipticCurve(GF(M), [0, 0, 0, a, b]) | |
base = E([5234568, 2287747]) | |
pub = E([2366653, 1424308]) | |
c1 = E([5081741, 6744615]) | |
c2 = E([610619, 6218]) | |
X = base | |
for i in range(1, M): | |
if X == pub: | |
secret = i | |
print "[+] secret:", i | |
break | |
else: | |
X = X + base | |
print i | |
#secret = 1584718 | |
m = c2 - (c1 * secret) | |
print "[+] x:", m[0] | |
print "[+] y:", m[1] | |
print "[+] x+y:", m[0] + m[1] | |
# [+] x+y: 5720914 |
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