Solution to the Project Euler problem #1 - For the multigrad blog (entry 2)

euler1_s2.py

# Algorithm
from itertools import chain
sum(set(x for x in chain(range(5, 1000, 5), range(3, 1000, 3))))

# To benchmark it
import timeit
timeit.timeit(
  "sum(set(x for x in chain(range(5, 1000, 5), range(3, 1000, 3))))",
  setup="from itertools import chain",
  number=10000
) / 10000.