python:回文数字判断第二波

gistfile1.py

i = 1281854581821
def getReverse(base, num):
  if num < 10:
		return base*10 + num
	return getReverse(base*10+num%10, num/10)
	
def getReverse1(num):
	i = 0
	while num:
		i = i*10 + num%10
		num /= 10
	return i

def isPalindrome(num):
	return num == getReverse(0, num)

print (isPalindrome(i))