Created
December 26, 2017 02:16
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Leetcode #331. Verify Preorder Serialization of a Binary Tree
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class Solution { | |
public: | |
/* | |
Intuition: | |
1) every node has to be a left or right child of some node, except the root ofcourse | |
2) every non "#" node means it has 2 leaves so a valid preorder string would have 2 more values | |
3) Using 1 and 2, set totalnodes = 0. Add 2 to totalnodes if non "#" value encountered and decrement totalnodes for having processed present value | |
4) Using this scheme, totalnodes should equal 0 at end if it's a valid preorder string. | |
5) We start with totalnodes = 1 instead of 0 cause inside loop it does totalnodes-- for every value , which includes | |
root value as well. | |
*/ | |
bool isValidSerialization(string preorder) { | |
stringstream ss(preorder); | |
string nodevalue; | |
int totalnodes = 1; | |
while(getline(ss, nodevalue, ',')){ | |
totalnodes--; | |
if(totalnodes < 0) return false; | |
if(nodevalue != "#") totalnodes += 2; | |
} | |
return totalnodes == 0; | |
} | |
}; |
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