Created
April 29, 2013 15:38
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Simple Sparse Linear Solver
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// | |
// Sparse LU Decomposition (Gilbert-Peierls) | |
// | |
#include <iostream> | |
#include <cstdio> | |
#include <cstdlib> | |
#include <vector> | |
#include <functional> | |
#include <algorithm> | |
#include <cmath> | |
#include <map> | |
using namespace std; | |
#define ALL(c) c.begin(), c.end() | |
#define FOR(i,c) for(typeof(c.begin())i=c.begin();i!=c.end();++i) | |
#define FORR(i,c) for(typeof(c.rbegin())i=c.rbegin();i!=c.rend();++i) | |
#define REP(i,n) for(int i=0;i<n;++i) | |
#define fst first | |
#define snd second | |
// Simplified Compressed Row Storage | |
typedef pair<int, double> Entry; | |
typedef vector<Entry> Row; | |
typedef vector<Row> Matrix; | |
const double EPS = 1e-8; | |
// LU decomposition without reordering (Gilbert-Peierls) | |
// | |
// Note: A is LU-decomposable <=> all principal minors are nonsingular | |
map<int,double> Lsolve(const Matrix &L, const Row &b) { | |
map<int, double> x; | |
FOR(e, b) x[e->fst] = e->snd; | |
FOR(e, x) FOR(l, L[e->fst]) | |
x[l->fst] -= l->snd * e->snd; | |
return x; | |
} | |
Row Usolve(Matrix U, map<int, double> b) { | |
FORR(e, b) FORR(u, U[e->fst]) | |
if (u->fst == e->fst) e->snd /= u->snd; | |
else b[u->fst] -= u->snd * e->snd; | |
Row x; | |
FOR(e, b) x.push_back(*e); | |
return x; | |
} | |
pair<Matrix, Matrix> LUdecomposition(Matrix A) { | |
int n = A.size(); | |
Matrix L(n), U(n); | |
REP(k, n) { | |
map<int, double> s = Lsolve(L, A[k]); | |
map<int, double>::iterator j = s.find(k); | |
double D = (j++)->snd; | |
U[k].assign(s.begin(), j); | |
L[k].assign(j, s.end()); | |
FOR(l, L[k]) l->snd /= D; | |
} | |
return make_pair(L, U); | |
} | |
int main() { | |
int n = 100; | |
Matrix A(n); | |
REP(i, n) { | |
if (i == n-1) A[i].push_back( Entry(0, 1) ); | |
if (i-2 >= 0) A[i].push_back( Entry(i-2, 3) ); | |
if (i-1 >= 0) A[i].push_back( Entry(i-1, 4) ); | |
A[i].push_back( Entry(i , 5) ); | |
if (i+1 < n) A[i].push_back( Entry(i+1, 2) ); | |
if (i == 0) A[i].push_back( Entry(n-1, 1) ); | |
} | |
// M = |5 4 3 1| | |
// |2 5 4 3 | | |
// | 2 5 4 3 | | |
// | 2 5 4 3| | |
// | 2 5 4| | |
// |1 2 5| | |
Row x; | |
REP(i, n) x.push_back( Entry(i, i+1) ); | |
// x = [1,2,...,n]' | |
pair<Matrix,Matrix> LU = LUdecomposition(A); | |
x = Usolve( LU.snd, Lsolve( LU.fst, x ) ); | |
FOR(e, x) printf("%d %lf\n", e->fst, e->snd); | |
} |
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