Fizz Buzz in Haskell

gistfile1.hs

-- Feels like there's a shorthand for the duplicated `mod` expressions.

fizzBuzz x
  | (x `mod` 3) == 0 && (x `mod` 5) == 0 = "FizzBuzz"
  | (x `mod` 3) == 0 = "Fizz"
  | (x `mod` 5) == 0 = "Buzz"
  | otherwise = show x

-- Extracting the mod expressions in any way I know how (so far) leads to more complication.

Guard Clauses depend on sequence. Always has been; always will be.

I think this is about as good as mine's going to get: https://gist.github.com/jbrains/2a29465457bddcca0c45