Created
November 7, 2015 17:34
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NHAY solution
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#include<cstdio> | |
#include<climits> | |
typedef long long int lli; | |
void calcLps(char *pat, lli *lps, lli& m){ | |
lli j = 0; | |
lli i = 1; | |
lps[0] = 0; | |
while (i < m){ | |
while (pat[j] != pat[i]){ | |
if (j == 0) | |
break; | |
j = lps[j - 1]; | |
} | |
lps[i] = j + 1; | |
j++; i++; | |
} | |
} | |
int main(){ | |
#ifdef _DEBUG | |
freopen("input.txt", "r", stdin); | |
#endif | |
lli m; | |
char * pat; | |
lli *lps; | |
char Text; | |
while (scanf("%lld", &m) != EOF){ | |
pat = new char[m]; | |
scanf("%s\n", pat); | |
lps = new lli[m]; | |
calcLps(pat, lps, m); | |
lli i = 0; | |
lli textCount = 0; | |
lli res = -1; | |
while (scanf("%c", &Text)!=EOF){ | |
if (Text == '\n'){ | |
printf("\n"); | |
break; | |
} | |
if (i < m){ | |
while (i != 0 && Text != pat[i]){ | |
i = lps[i - 1]; | |
} | |
if (Text==pat[i]) | |
i++; | |
} | |
textCount++; | |
if (i == m){ | |
i = lps[i - 1]; | |
res = textCount - m; | |
printf("%d\n", res); | |
} | |
} | |
if (res == -1) | |
printf("\n"); | |
} | |
return 0; | |
} |
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