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@srkama
Forked from pdu/leetcode_edit_distance.cpp
Created September 18, 2018 11:22
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Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.) You have the following 3 operations permitted on a word: a) Insert a character b) Delete a character c) Replace a character http://leetcode.com/onlinejudge#question_72
#define MAXN 500
int f[MAXN][MAXN];
int dp(int f[MAXN][MAXN], string& word1, string& word2, int n, int m, int k, int t) {
if (k < 0)
return t + 1;
if (t < 0)
return k + 1;
if (f[k][t] != -1)
return f[k][t];
if (word1[k] == word2[t])
return f[k][t] = dp(f, word1, word2, n, m, k - 1, t - 1);
f[k][t] = max(n, m);
f[k][t] = min(f[k][t], dp(f, word1, word2, n, m, k - 1, t - 1) + 1);
f[k][t] = min(f[k][t], dp(f, word1, word2, n, m, k - 1, t) + 1);
f[k][t] = min(f[k][t], dp(f, word1, word2, n, m, k, t - 1) + 1);
return f[k][t];
}
class Solution {
public:
int minDistance(string word1, string word2) {
int n = word1.size();
int m = word2.size();
memset(f, -1, sizeof(f));
return dp(f, word1, word2, n, m, n - 1, m - 1);
}
};
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