XSL to determine all tag paths in an XML file.

xmlpaths.xsl

<?xml version="1.0"?>
<!--
	Stylesheet to list all tag-name paths in an XML file, including attributes.

	2013 Sven-S. Porst <porst@sub.uni-goettingen.de>
-->
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

	<xsl:output method="text" />

	<xsl:template match="node()">
		<xsl:for-each select="ancestor-or-self::*">
			<xsl:value-of select="concat('/',name(.))"/>
		</xsl:for-each>
		<xsl:text>&#xA;</xsl:text>

		<xsl:apply-templates select="*|@*"/>
	</xsl:template>

	<xsl:template match="@*">
		<xsl:for-each select="ancestor::*">
			<xsl:value-of select="concat('/',name(.))"/>
		</xsl:for-each>
		<xsl:text>/@</xsl:text>
		<xsl:value-of select="name(.)"/>
		<xsl:text>&#xA;</xsl:text>
	</xsl:template>

</xsl:transform>

zUsage.md

Create a sorted list of occurring tag paths:

xsltproc xmlpaths.xsl input.xml | sort --unique

… with a tag count

xsltproc xmlpaths.xsl input.xml | sort | unique -c

Sorted list of tag paths of all XML files within the current folder (slow)

find . -name "*.xml" | xargs xsltproc ~/Desktop/xmlpaths.xsl | sort --unique

Other strategy, extract and store tag names file-by-file, use parallel processing, unique tags from each file first, then concatenate and unique again.

mkdir /tmp/xsltproct find . -name ".xml" | xargs -P 8 -I FILE xsltproc --output /tmp/xslttmp/FILE.out xmlpaths.xsl FILE | sort --unique find /tmp/xslttmp/ -name ".out" | xargs -P 8 -I FILE sort --unique --output=FILE.uniq FILE find . -name "*.out.uniq" | xargs cat > cat.all sort --unique cat.all

Excellent work! You've made my day a lot easier :)