Checking condition in an infinitely nested loop with BFA search , implemented in python

check.py

a = [[1,2,[3,4,5]],6,[7,[8,9,10,[11,12,13]]]]


def qq(a) :
  current = a
  next = []

  while (current or current == 0) :
    if(type(current) is int and current > 7) :
      return current
    if(type(current) is list ) :
      for i in current :
        next.append(i)
    current = next[0]
    next = next[1:]
  return "Nope"

print(qq(a))

Javascript :
current = next.shift()