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April 11, 2020 10:41
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JavaScript Binary Search
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const sortedArray = [1,3,5,5,7,8,11,12,14,14,15,16,16,17,17,17,17,18,19,19,19]; | |
const bs = (arr, target) => { | |
let start = 0; | |
let end = arr.length - 1; | |
let tries = 1; | |
while(start <= end){ | |
console.log("TRY NUMBER ", tries); | |
let middle = Math.floor((start + end)/ 2); | |
console.log("end is ", end) | |
console.log("start is ", start) | |
console.log(`looking now at position ${middle} where the value is ${arr[middle]}`) | |
console.log("\n") | |
if(arr[middle] === target){ | |
console.log("found the target at this location!! : ", arr[middle]); | |
return true; | |
} | |
else if(arr[middle] > target){ | |
console.log("target is smaller than the midpoint so next look to the left half of the array" ) | |
end = middle-1 | |
} | |
else{ | |
console.log("target is bigger than the midpoint so next look to the right half of the array" ); | |
start = middle+1; | |
} | |
tries ++; | |
} | |
return false | |
} | |
bs(sortedArray, 18) |
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