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Rapid Publishing of Messages on PubNub. You can publish message efficiently using this mechanism. How efficient you ask? This method allows you to publish upwards of 30 messages **Per TCP Packet!**. Wow. See https://gist.github.com/stephenlb/9496723 for more information.
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import socket | |
import uuid | |
import random | |
import threading | |
import time | |
import random | |
import math | |
HOST = 'pubsub.pubnub.com' | |
PORT = 80 | |
numID = random.randrange(5000, 10000) | |
print 'creating', numID, ' UUIDs' | |
id = [] | |
for x in range(0, numID-1): | |
id.append(uuid.uuid4()) | |
print 'We will send a random quantity of messages every 10 seconds, each contains a randomly selected UUID.' | |
def socketPool(message): | |
#TODO: Implement socketPool w/ size 100 | |
def handleSocketRead(s): | |
while True: | |
try: | |
msg = s.recv(4096) | |
except socket.timeout, e: | |
err = e.args[0] | |
print 'recv timed out, done reading' | |
break | |
except socket.error, e: | |
print e | |
break | |
else: | |
continue | |
#print repr(msg) | |
def send(): | |
time.sleep(10) | |
threading.Thread(target=send).start() | |
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) | |
s.connect((socket.gethostbyname(HOST), PORT)) | |
s.settimeout(2) | |
numMessages = random.randrange(math.floor(0.5*numID), 2*numID) | |
print 'Sending '+ str(numMessages) +' messages.' | |
time_start = time.time() | |
tmr = threading.Thread(target=handleSocketRead, args=[s]) | |
tmr.start() | |
for message in range(0, numMessages): | |
#print 'we are on message', message+1, 'of', numMessages | |
s.send('GET /publish/pub-c-5afaf11d-aa91-4a40-b0d2-77961fb3a258/sub-c-0cd3a376-28ac-11e4-95a7-02ee2ddab7fe/0/HyperLogLogDemo1/0/"'+str(id[random.randrange(0, numID-1)])+'" HTTP/1.1\r\nHost: pubsub.pubnub.com\r\n\r\n') | |
print 'It took', str(time.time()-time_start), 'runtime to send', numMessages, 'messages' | |
handleSocketRead(s) | |
s.close() | |
## Send Messages Quickly | |
if __name__ == "__main__": | |
send() |
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