Created
June 12, 2016 02:24
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Comparing lists for equal/sublist/superlist
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defmodule Sublist do | |
def compare(a,b) when a === b, do: :equal | |
def compare(a,b) do | |
cond do | |
a === b -> :equal | |
sublist?(a,b) -> :sublist | |
sublist?(b,a) -> :superlist | |
true -> :unequal | |
end | |
end | |
defp sublist?([],_), do: false | |
defp sublist?(_,[]), do: false | |
defp sublist?(first, second=[_|tail]) do | |
if at_head?(first, second) do | |
true | |
else | |
sublist?(first, tail) | |
end | |
end | |
defp at_head?([],_), do: true | |
defp at_head?(_,[]), do: false | |
defp at_head?([a|restA], [a|restB]) do | |
at_head?(restA,restB) | |
end | |
defp at_head?(_,_), do: false | |
end | |
ExUnit.start | |
defmodule SublistTest do | |
use ExUnit.Case, async: true | |
test "A is a sublist of B(1)" do | |
assert :sublist == Sublist.compare([1,2,3], [1,2,3,4,5]) | |
end | |
test "A is a sublist of B(2)" do | |
assert :sublist == Sublist.compare([3,4,5], [1,2,3,4,5]) | |
end | |
test "A is a sublist of B(3)" do | |
assert :sublist == Sublist.compare([3,4], [1,2,3,4,5]) | |
end | |
test "A = B" do | |
assert :equal == Sublist.compare([1,2,3], [1,2,3]) | |
end | |
test "A is a superset of B" do | |
assert :superlist == Sublist.compare([1,2,3,4,5], [2,3,4]) | |
end | |
test "A is not a superset of B" do | |
assert :unequal == Sublist.compare([1,2,4], [1,2,3,4,5]) | |
end | |
test "A is not a subset of B" do | |
assert :unequal == Sublist.compare([1,2,3,4,5], [1,2,4]) | |
end | |
test "A is not equal to B" do | |
assert :unequal == Sublist.compare([1,2,4], [1,2,3,4,5]) | |
end | |
test "Empty list is in B" do | |
assert :unequal == Sublist.compare([],[1,2,3]) | |
end | |
test "A is not in empty" do | |
assert :unequal == Sublist.compare([1,2,3], []) | |
end | |
end |
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