Interview Coding Problems

arrange.ts

// this problem is written by metis200, and can be found at https://github.com/metis200/FE-Exam
/**
 * --- 问题描述 ---
 *
 * 实现一个 arrange 函数，可以进行时间和工作调度
 *
 * --- 说明 ---
 *
 * - 本题需要自己实现测试用例
 * - 具体功能参考下列示例
 * - 在示例中调用到的方法都需要实现
 * - 下面示例中 `>` 表示在控制台中输出 (console.log)
 *
 * --- 示例 ---
 *
 * 示例一:
 * `arrange('William').execute();`
 * > William is notified
 *
 * 示例二:
 * `arrange('William').wait(5).do('commit').execute();`
 * > William is notified
 * 等待 5s...
 * > Start to commit
 *
 * 示例三:
 * `arrange('William').waitFirst(3).do('push').execute();`
 * 等待 3s...
 * > William is notified
 * > Start to push
 *
 */

function arrange(name) {
    async function sleep(timeInSecond) {
        return new Promise((resolve) => {
            setTimeout(() => {
                resolve();
            }, timeInSecond * 1000);
        });
    }
    class Arrangement {
        constructor(name) {
            this.f = async () => {
                console.log(`${name} is notified`);
            }
        }
        waitFirst(time) {
            const oldFn = this.f;
            const newFn = () => {
                return new Promise((resolve) => {
                    setTimeout(() => {
                        resolve(oldFn());
                    }, time * 1000);
                });
            }
            this.f = newFn;
            return this;
        }
        wait(timeInSecond) {
            const oldFn = this.f;
            const newFn = () => {
                return oldFn().then(() => {
                    return sleep(timeInSecond);
                });
            }
            this.f = newFn;
            return this;
        }
        do(actionText) {
            const oldFn = this.f;
            const newFn = () => {
                return oldFn().then(() => {
                    console.log(`Start to ${actionText}`);
                });
            }
            this.f = newFn;
            return this;
        }
        execute() {
            return this.f();
        }
    }
    return new Arrangement(name);
}