Solution for λ Talks in Yangon registration quiz

quiz.scala

def multiply(x: Double, n: Double): Double = {
  if (n == 0) 0 else x + multiply(x, n - 1)
}

def power(b: Int, e: Int): Double = {
  if (e > 0) multiply(b.toDouble, power(b, e - 1))
  else if (e < 0) 1/power(b, -e) // let me use / for negative e :P
  else 1.0
}

power(2, 8) // 256.0
power(2, -8) //0.00390625

kyite tal kwar