Find unused sass variables. Inspired from https://gist.github.com/badsyntax/6193491

unused-variables.sh

#!/usr/bin/env bash
#
# Approach:
# 1. Find variable declaration in the form of "$my-var: anyvalue"
# 2. Loop through found variables and find occurrences of each variable in all sass files
# 3. Filter out vars that occurred only once

# Usage:
# Create a file (e.g. unused-variables.sh) having the below code, place it outside your sass folder.
# Run chmod +x ./unused-variables.sh to give execute permission to your script.
# Run ./unused-variables.sh sass

if [ -z "$1" ]; then
        echo "Please specify a directory as the first argument."
        exit 1
fi
if [ ! -d "$1" ]; then
        echo "Not a valid directory."
        exit 1
fi

echo "Finding unused variables. This might take some time..."

#vars=$(find "$1" -type f -name "*.scss" -exec grep --color=never -h '^$[a-zA-Z0-9_-][^:]*' {} \; | sed 's/$\([a-zA-Z0-9_-][^:]*\).*/\1/')

#for var in $vars; do
#       echo -n "Occurrences of \"\$$var\":"
#       find "$1" -type f -name "*.scss" -exec grep --color=never -h "$var" "{}" \; | wc -l
#done | grep ' 1$'

varNameChars='A-Za-z0-9_-'
vars=$(find "$1" -type f -name "*.scss" -exec grep -o "\$[$varNameChars]*:" {} \; | grep -o '[^:]*')
for var in $vars; do
    echo -n $var
    find "$1" -type f -name "*.scss" -exec grep -o $var"[^$varNameChars]" {} \; | wc -l
done | grep ' 1$'