An implementation of quicksort
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'use strict' | |
const nums = [3, 0, 2, 5, 1, 3, 0] | |
quicksort(nums, 0, nums.length - 1) | |
console.log(nums) | |
const chars = ['z', 'a', 'u', 'f', 'f', 'A'] | |
quicksort(chars, 0, chars.length - 1) | |
console.log(chars) | |
// quicksort is at worst O(n^2), on averago O(n log n) | |
// | |
// TODO implement a better way of choosing pivot point in order to | |
// reduce the chance that the pivot will be the highest or lowest | |
// value in the element, which would cause it to run be O(n^2) | |
function quicksort (arr, lo, hi) { | |
if (lo < hi) { | |
const pivotIndex = partition(arr, lo, hi) | |
quicksort(arr, lo, pivotIndex - 1) // sort the low partition | |
quicksort(arr, pivotIndex + 1, hi) // sort the high partition | |
} | |
} | |
function partition (arr, lo, hi) { | |
const pivot = arr[hi] // the element to compare against | |
let wall = lo // the index to swap at | |
for (let i = lo; i < hi; i++) { | |
// if the current element is less than the pivot, swap it with the | |
// index at wall and move the wall over by one | |
if (arr[i] < pivot) { | |
swap(arr, i, wall) | |
wall++ | |
} | |
} | |
swap(arr, hi, wall) | |
return wall | |
} | |
function swap (arr, i, j) { | |
const tmp = arr[i] // swap in-place O(1) | |
arr[i] = arr[j] | |
arr[j] = tmp | |
} |
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