rock paper scissors in python for practice.

rockPaperScissors.py

import random

def computerChoice():
    random.seed()
    a = random.randint(1,3)
    choices = ["rock", "scissors", "paper"]
    return choices[a - 1] ''' if a is 1, it'll return choices[0] which is rock, etc. '''

    '''
    if(a == 1):
        computer = "rock"
    elif(a == 2):
        computer = "scissors"
    elif(a == 3):
        computer = "paper"
    return computer
    '''

b = 1
while(b == 1):
    print("How many times do you wish to play?")
    play = int(input())
    for i in range (0, play): ##Note to self: this is correct because python excludes the stop range. For instance if I enter 3, it will go 0,1,2
        print("type either rock, paper, or scissors.")
        user = input().lower()
        cc = computerChoice()
        '''
        Bro, just check if the user input and the computerChoice are equal
        not all this shit
        # if(user.lower() == "rock" and computerChoice() == "rock"):
        #     print("tie")
        # elif (user.lower() == "scissors" and computerChoice() == "scissors"):
        #     print("tie")
        # elif (user.lower() == "paper" and computerChoice() == "paper"):
        #     print("tie")
        '''
        if user == cc:
            print("tie")
        elif (user.lower() == "rock" and computerChoice() == "scissors"):
            print("win")
        elif (user.lower() == "scissors" and computerChoice() == "paper"):
            print("win")
        elif (user.lower() == "paper" and computerChoice() == "rock"):
            print("win")
        elif (user.lower() == "scissors" and computerChoice() == "rock"):
            print("lose")
        elif (user.lower() == "paper" and computerChoice() == "scissors"):
            print("lose")
        elif (user.lower() == "rock" and computerChoice() == "paper"):
            print("lose")
    print("if you wish to continue type 1 but if not type any other number")
    b = (int)(input())

removed semicolons, compacted code