SPARQLWrapper example: List all predicates of DBPedia Band class

sparql_list_predicates_band.py

from SPARQLWrapper import SPARQLWrapper, JSON

query = """
SELECT distinct ?subject
FROM <http://dbpedia.org>
{
   ?subject rdfs:domain ?object .
   <http://dbpedia.org/ontology/Band> rdfs:subClassOf ?object
   OPTION (TRANSITIVE, t_distinct, t_step('step_no') as ?n, t_min (0) ).
}"""

sparql = SPARQLWrapper("http://dbpedia.org/sparql")
sparql.setQuery(query)
sparql.setReturnFormat(JSON)
results = sparql.query().convert()

for result in results["results"]["bindings"]:
    print(result["subject"]["value"])

Hi Tatiana,

Thanks for your nice work. If I want to print the query result in JSON format, I have to put the variable name manually in the print statement which is a major drawback of this approach. Is there any way to print the result as just tabular/text format? For example please see the attached image