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Print-based debugger for recursive procedures
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| # If you run this program: | |
| def fibo(n): | |
| print '>>' | |
| ret = 1 if n == 0 or n == 1 else fibo(n - 1) + fibo(n - 2) | |
| print "Got %d, returning %d." % (n, ret) | |
| print '<<' | |
| return ret | |
| fibo(5) | |
| # And put its output as input to recdebug, you get: | |
| """ | |
| >> | |
| >> | |
| >> | |
| >> | |
| Got 1, returning 1. | |
| << | |
| >> | |
| Got 0, returning 1. | |
| << | |
| Got 2, returning 2. | |
| << | |
| >> | |
| Got 1, returning 1. | |
| << | |
| Got 3, returning 3. | |
| << | |
| >> | |
| >> | |
| Got 1, returning 1. | |
| << | |
| >> | |
| Got 0, returning 1. | |
| << | |
| Got 2, returning 2. | |
| << | |
| Got 4, returning 5. | |
| << | |
| """ |
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| #! /usr/bin/env python | |
| import sys | |
| def recdebug(input): | |
| output = '' | |
| lvl = 0 | |
| for l in input: | |
| if l == "<<": | |
| lvl -= 1 | |
| output += ("\t" * lvl) + l + '\n' | |
| if l == ">>": | |
| lvl += 1 | |
| return output | |
| if __name__ == '__main__': | |
| import sys | |
| print recdebug(sys.stdin.read()) |
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Should that work?
python example.py | recdebug