PowerShell function that takes a fully provided path to a file and returns just the file name of that path

get-filename

<#
.Synopsis
    Returns file name from full file path
.DESCRIPTION
    Takes a fully provided path to a file and returns just the file name of that path
.EXAMPLE
    Get-FileName -FilePath C:\afolder\afile.txt

    Returns just the filename from the fully provided path
.EXAMPLE
    Get-FileName -FilePath $ImagePath -Verbose

    Returns just the filename from the fully provided path in $ImagePath with verbose output
.PARAMETER FilePath
    Full file sytem path to specified file
.OUTPUTS
    System.String
.NOTES
    Author: Jake Morrison - @jakemorrison - http://techthoughts.info/
#>
function Get-FileName {
    [CmdletBinding()]
    Param
    (
        [Parameter(Mandatory = $true,
            HelpMessage = 'Full path to file')]
        [ValidateNotNull()]
        [ValidateNotNullOrEmpty()]
        [string]$FilePath
    )
    Write-Verbose -Message "Processing $FilePath ..."
    #-------------------------------------------------
    #$divide = $FilePath.Split("\")
    #$fileName = $divide[$divide.Length - 1]
    #$results = $fileName
    #-------------------------------------------------
    $results = ""
    try {
        $fileInfo = Get-ChildItem -Path $FilePath -ErrorAction Stop
        $fileName = $fileInfo.Name
        Write-Verbose -Message "Filename is: $fileName"
        $results = $fileName
    }#try_Get-ChildItem
    catch {
        Write-Warning "The file information for $FilePath could not be determined."
        $results = "ERROR"
    }#catch_Get-ChildItem
    return $results
}#function_Get-FileName