Anagrams interview test with some broken features

Broken_Anagrams_PR.cs

public static void printAnagramList(String[] words)
{
    // Store anagram groups
    var groupings = new Dictionary<string, string>();
    for (int i = 1; i < words.Length; i++)
    {
        var ws = GetSortedWord(words[i]);
        for (int j = (i + 1); j < words.Length; j++)
        {
            char[] word2 = words[j].ToCharArray();
            Array.Sort(word2);
            // Helpful to compare things later
            var wsss = (new string(word2));
            // If the sorted string are equal, they have the same length and letter
            // occurrences. However, we don't want to deal with them if they are the
            // exact same word, which can happen in subsequent loops
            if (ws.Equals(wss) && !words[i].Equals(words[j]))
            {
                // if our groupings already contain the key, append our current word
                if (groupings.ContainsKey(ws))
                {
                    // if the word is already in the group, don't add it again
                    if (!groupings[ws].Split(',').Contains(words[j]))
                    {
                        groupings[ws] += "," + words[j];
                    }
                    else
                    {
                        // we don't have a new key/group started yet, let's create one
                        groupings.Add(ws, words[i] + "," + words[j]);
                    }
                }
            }
        }
    // output all groupings on their own line
    foreach (var key in groupings.Keys)
    {
        Console.WriteLine(groupings[key]);
    }}
}
 
public static string GetSortedWord(string word)
{
    char[] word_char = word.ToCharArray();
    Array.Sort(word_char);
    return (new string(word_char));
}