gistfile1.txt

	public class Dog {
		public static void main(String[] args) {
			Dog aDog = new Dog("Max");
			foo(aDog);
			aDog.name.equals("Max"); // true
		}
		public static void foo(Dog d) {	        
			d.name.equals("Max"); // true
			d = new Dog("Fifi");
			d.name.equals("Fifi"); // true
		}
		
		public String name;
		public Dog(String name){
			this.name = name;
		}
	}

Paste it here: http://cscircles.cemc.uwaterloo.ca/java_visualize/#mode=display

Java is always pass-by-value. The difficult thing can be to understand that Java passes objects as references passed by value.
In this example aDog.name will still be "Max". "d" is not overwritten in the function as the object reference is passed by value.
(http://stackoverflow.com/questions/40480/is-java-pass-by-reference)