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@thejsj
Created January 9, 2013 19:11
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def all_perms(elements):
if len(elements) <=1:
yield elements
else:
for perm in all_perms(elements[1:]):
for i in range(len(elements)):
#nb elements[0:1] works in both string and list contexts
yield perm[:i] + elements[0:1] + perm[i:]
@EML-student
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So I'm pretty new to recursive programming. How does this generate all possible permutations. The line "for perm in...." should it not find all characters in elements?

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