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SECCON 2020 Online CTF - solution for crypto01
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def decrypt(c, d, n): | |
size = n.bit_length() // 2 | |
c_high, c_low = c | |
b = (c_low**2 - c_high**3) % n | |
EC = EllipticCurve(Zmod(n), [0, b]) | |
m_high, m_low = (EC((c_high, c_low)) * d).xy() | |
m_high, m_low = int(m_high), int(m_low) | |
return (m_high << size) | m_low | |
def contfrac(x, y): | |
""" | |
calculate continuated fraction of x/y | |
""" | |
while y: | |
a = x // y | |
yield a | |
x, y = y, x - a * y | |
def covergents(e, n): | |
numerator, denominator = 1, 0 | |
numerator2, denominator2 = 0, 1 | |
for x in contfrac(e, n): | |
numerator, numerator2 = x * numerator + numerator2, numerator | |
denominator, denominator2 = x * denominator + denominator2, denominator | |
yield numerator, denominator | |
def solve(n, e, plow): | |
low_size = int(plow).bit_length() | |
approx_size = (int(n).bit_length() // 2 - low_size) // 2 - 8 | |
print("known: {}, approx: {}".format(low_size, approx_size)) | |
for cov in covergents(e, n): | |
x, y = cov | |
if x == 0: | |
continue | |
if x * x > n: | |
continue | |
u = round(e*y / x - n - 1) | |
v = round(sqrt(abs(u**2 - 4 * n))) | |
if u < 0: | |
continue | |
p_ = Integer(u + v) // 2 | |
size = p_.nbits() - approx_size | |
p_ = (p_ >> size) << size | |
PR, x = PolynomialRing(Zmod(n), name="x").objgen() | |
f = x*2**low_size + plow + p_ | |
f = f.monic() | |
roots = f.small_roots(X=2**(size - low_size), beta=0.5, epsilon=0.05) | |
for r in roots: | |
p = int(p_ + plow + r * 2 ** low_size) | |
if n % p == 0: | |
return p, n // p | |
return None, None | |
exec(open("output.txt").read()) | |
# set_verbose(2) | |
for param in ciphertexts: | |
n, e, c, hint = param["n"], param["e"], param["c"], param["hint"] | |
p, q = solve(n, e, hint) | |
d = inverse_mod(e, (p+1)*(q+1)) | |
masked_flag = masked_flag ^^ decrypt(c, d, int(n)) | |
print(bytes.fromhex(hex(masked_flag)[2:])) |
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