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import java.util.*; | |
public class LongestCommonSubsequenceDPTopDown { | |
static HashMap<String, Integer> hm = new HashMap<>(); | |
public static int LCS(String A, String B) { | |
if (A.length() == 0 || B.length() == 0) { | |
return 0; | |
} | |
if(hm.containsKey(A+B)){ | |
return hm.get(A+B); | |
} | |
int lenA = A.length(); | |
int lenB = B.length(); | |
// check if last characters are same | |
if (A.charAt(lenA - 1) == B.charAt(lenB - 1)) { | |
// Add 1 to the result and remove the last character from both | |
// the strings and make recursive call to the modified strings. | |
int x = LCS(A.substring(0, lenA - 1), B.substring(0, lenB - 1)); | |
hm.put(A.substring(0, lenA - 1)+ B.substring(0, lenB - 1), x); | |
return 1 + x; | |
} else { | |
// Remove the last character of String 1 and make a recursive | |
// call and remove the last character from String 2 and make a | |
// recursive and then return the max from returns of both recursive | |
// calls | |
int y = LCS(A.substring(0, lenA - 1), B.substring(0, lenB)); | |
int z = LCS(A.substring(0, lenA), B.substring(0, lenB - 1)); | |
hm.put(A.substring(0, lenA - 1)+ B.substring(0, lenB), y); | |
hm.put(A.substring(0, lenA)+ B.substring(0, lenB-1), z); | |
return Math.max(y, z); | |
} | |
} | |
public static void main(String[] args) { | |
String A = "ACBDEABCSBEDACBDEABCSBEDACBDEABCSBEDACBDEABCSBED"; | |
String B = "ABCDASBDABCDASBDABCDASBDABCDASBD"; | |
System.out.println("LCS :" + LCS(A, B)); | |
} | |
} |
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