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@threeifbywhiskey
Created August 9, 2014 00:43
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This is a brainfuck interpreter written in a pseudo-assembly language which maps onto Whitespace's instructions.
; brainfuck interpreter in Whitespace assembly
; To facilitate the interpretation of "literate" brainfuck, consecutive newlines
; are used to signal the end of program input. Thus, the previous character must
; be remembered. Also, non-brainfuck characters must be passed over silenty. The
; heap is used for these processes to avoid having to juggle the stack too much.
push ,
push .
push <
push >
push 45
push 43
push 0
push -7
; Store the brainfuck commands and previous character in negative heap space.
0:
swap
copy 1
swap
store
push 1
add
dup
jn 0
; Initialize the tape at the front of the heap.
1:
dup
push 30000
sub
jz 2
dup
push 0
store
push 1
add
jump 1
; Read in instructions, storing them at index 30000 on. Bracket pairs are also
; processed here; jumps (in both directions) are stored beginning at 40000. As
; such, programs are limited to 10000 instructions, but that seems sufficient.
2:
dup
dup
ichr
load
dup
push -7
load ; Get previous character.
mul
push 100 ; Only two consecutive newlines will have a product of 100.
sub
jz 9 ; Done reading instructions, begin executing.
push -7
copy 1
store ; Update previous character.
dup
push [
sub
jz 7
dup
push ]
sub
jz 8
push 10
sub
jz 2
dup
load
push -6 ; Character isn't a bracket or newline, flow into validator.
; Test the current character against each brainfuck command.
3:
dup
jz 4 ; All commands tested, no match found.
dup
load
copy 2
sub
jz 5 ; Found one, return early.
push 1
add
jump 3 ; Try again.
; Character wasn't a command, don't increment the instruction pointer to allow
; the next character to overwrite it.
4:
pop
pop
jump 2
; Valid instruction found, flow into incrementer.
5:
pop
pop
; Increment instruction pointer.
6:
push 1
add
jump 2
; Bury the index of the current left bracket under the instruction pointer.
7:
pop
dup
swap
jump 6
; Match a right bracket with the most recent left and store the indices at the
; corresponding locations in the heap. For instance, the heap for the alphabet
; program (+[.+]) would be {40001: 30004, 40004: 30001}.
8:
pop
swap
copy 1
copy 1
push 10000
add
swap
store
copy 1
push 10000
add
swap
store
jump 6
; Prepare the stack for program execution. [instruction pointer, stack pointer]
9:
dup
sub
push 30000
swap
; Step through the instruction sequence and respond accordingly.
10:
copy 1
load
dup
push 10
sub
jz 18 ; Exit on newline.
dup
push 47
sub
jn 12 ; Handle IO (.,) and stack adjustment (+-).
dup
push >
swap
sub
jn 15 ; Handle loops ([]).
push 61 ; Otherwise, move the stack pointer (<>).
sub
add
11: ; Increment the instruction pointer, keep the stack pointer on top.
swap
push 1
add
swap
jump 10
; +,-. are ASCII 43-46, so they're all processed here.
12:
dup
push 2
mod
jz 13 ; If even, do IO.
push 44 ; Otherwise, inc/decrement the current stack value.
sub
copy 1
load
swap
sub
copy 1
swap
push 256
mod
store
jump 11
; IO
13:
push .
sub
jz 14
dup
ichr
jump 11
; Output the current stack value as a character.
14:
dup
load
ochr
jump 11
; Process loops.
15:
push [
sub
jz 16 ; Jump if left bracket.
dup
load ; Get current stack value.
jz 11 ; If 0, exit loop.
jump 17 ; Otherwise, jump to matching left bracket.
; Handle left brackets.
16:
dup
load
jz 17 ; End loop if the current stack value is 0.
jump 11 ; Otherwise, proceed as usual.
; Jump to just after the matching bracket in either direction.
17:
swap
push 10000
add
load
swap
jump 11
; Exit clean.
18:
slide 3
pop
exit
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