count total of subsequent string in a row

solution.py

# The goal is to count the frequency of subsequent strings in a row. 

def count_subsequent_str(str):
    str = str.lower()
    temp = {}
    for i in range(len(str) - 1):
        if not str[i] in temp:
            temp[str[i]] = 0
        if str[i] == str[i+1] and temp[str[i]] < 1:
            temp[str[i]] += 2
        elif str[i] == str[i+1] and temp[str[i]] > 1:
            temp[str[i]] += 1

    return temp

if __name__ == '__main__':
    result = count_subsequent_str("trial and error")
    print(result)
    
# {'t': 0, 'r': 2, 'i': 0, 'a': 0, 'l': 0, ' ': 0, 'n': 0, 'd': 0, 'e': 0, 'o': 0}