A script to choose high-entropy but memorial passphrases

dicewords.py

#!/usr/bin/python

"""
Script to generate passphrases according to the vocabular in:
http://world.std.com/~reinhold/diceware.wordlist.asc

To see why this might be a better algorithm for choosing a password:
https://blog.agilebits.com/2011/06/21/toward-better-master-passwords/

Usage: ./dicewords.py n m

n - number of words per phrase
m - number of phrases to print
"""

import requests
import re
import sys
import random

expr = re.compile(r"^([1-6]{5})\t(.+)")

def get_words():
  text = requests.get('http://world.std.com/~reinhold/diceware.wordlist.asc').text
  matches = [expr.match(line) for line in text.split("\n")]
  words = [match.group(2) for match in matches if match]
  assert(len(words) == 6 ** 5)
  return words

if __name__ == "__main__":
  if len(sys.argv) != 3:
    print __doc__
  else:
    n = int(sys.argv[1])
    m = int(sys.argv[2])

    words = get_words()

    for _ in xrange(m):
      print " ".join([random.choice(words) for _ in xrange(n)])