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September 11, 2019 20:05
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Project one rotation frame into another frame
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from scipy.spatial.transform import Rotation as R | |
import numpy as np | |
#Example of having to rotations in different coordinate systems (r&q), where we want to reporesent r inside q: | |
#r0, r1, r2, r3, r4, ..., rX (i.e. BRIX quaternionen) | |
#q0, q1, q2, q3, q4, ..., qX (i.e. Vive quaternionen) | |
# | |
#delta = q0.inv() * r0 | |
#delta1 = r0.inv() * r1 | |
#r1_in_q0 = r0 * delta * delta1 = q0 * delta1 | |
#... | |
#deltaX = r0.inv() * rX | |
#rX_in_q0 = r0 * delta * deltaX = q0 * deltaX | |
# Some test: Transformation by: q0 * d0_1 = q1 | |
#q0 = R.from_quat([0, 0, 0.7071, 0.7071]) | |
#q1 = R.from_quat([0.7071, 0.7071, 0, 0]) | |
#d_0_1 = q0.inv() * q1 | |
#print("diff " + str(d_0_1.as_quat())) | |
# Define some coordinate system "q" and "r" with some difference "d" | |
q0 = R.from_quat([0.7071, 0.7071, 0, 0]) | |
d = R.from_quat([1,1,1,1]) | |
r0 = q0 * d | |
# define some incremental rotations for "r" and "q" | |
t = [R.from_quat([np.cos(idx/2./np.pi), np.sin(idx/2./np.pi), 0, 0]) for idx in range(20)] | |
r = [r0] | |
q = [q0] | |
for idx in range(len(t)): | |
r.append(r[-1] * t[idx]) | |
q.append(q[-1] * t[idx]) | |
#print("r \n", [str(r_.as_quat()) for r_ in r]) | |
#print("q \n", [str(q_.as_quat()) for q_ in q]) | |
print("\ncheck if we can naively transform (should give the unit quat |0,0,0,+-1|):") | |
for idx in range(len(q)): | |
_r = r[idx] * d | |
print(str((q[idx].inv() * _r).as_quat())) # should give the unit quat |0,0,0,+-1| | |
print("\ncheck if we can transform by first projecting into the origin rotation r0 (should give the unit quat |0,0,0,+-1|):") | |
for idx in range(len(q)): | |
# first, get the rotation wrt. r | |
dr = r0.inv() * r[idx] | |
# second, transform coordinate system by "d", then rotate by "r" | |
_r = r0 * d.inv() * dr | |
# should give the unit quat |0,0,0,+-1| | |
print(str((q[idx].inv() * _r).as_quat())) |
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