Harmonic series

HarmonicSeries.cpp

#include <iostream>;
#include <string>;
#include <cmath>;
using namespace std;

int main()
{
	int n=0; //counter
	int t=0; //user-input number of iterations
	double young=0.0;  //the new sum
	double old=0.0;  //the last sum
	bool keep_going=true;

	cout << "How many times do you want to iterate?  ";
	cin >> t;
	
	while(keep_going==true)
	{
		//Add these lines so you can see the values as they iterate. Helps debug
		//use endl to pring one per line
		cout << "---------------------"  << endl;
		cout << "Loop # : " << n         << endl;
		cout << "old    : " << old       << endl;
		cout << "1+n    : " << 1+n       << endl;
		cout << "1/(1+n): " << 1/(1+n)   << endl; //look carefully at this line and the next
		cout << "1/(1+n): " << 1.0/(1+n) << endl; //see I added the .0
		cout << "1/(1+n): " << 1/(1.0+n) << endl; //same idea
		cout << "1/(1+n): " << (double)1/(1+n) << endl; //same idea again just a different way

		//you should see that the 1/(1+n) is getting "casted" to an integer
		//in other words is getting rounded to 0 when 1/2 or 1/3
		//look up type casting in c++ on goolge for more info

		//young=(old+1/(1+n)); 
		young=(old+1.0/(1+n));  //main function that adds the last value to a slightly smaller fraction


		cout << "young after computation: " << young << endl;

		old=young;

		n++;

		if(n==t)
			keep_going = false;
	}

	cout << "The total you requested is: " << young << endl;
	cout << "Would you kindly press a key to continue?";
	cin >> t;
	return 0;
}

Added two lines to the while loop so you can see the values of young and old at each iteration

Added a bunch of cout so you can see what is happening with the type casting