timoxley/Readme.md

## Readme.md

      
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    JS Pop Quiz: How well do you know your functions?

Given an Array of Functions fns, what argument(s) can you pass to fns.forEach such that each function in fns will execute, in order, without creating any anonymous (or named) functions or invoking the Function constructor?
Conditions


Do not use the function keyword, or arrow functions () => .
Do not invoke the Function constructor.
Do not use method definitions.
Function#bind & friends on the Function.prototype are ok.
Answer should be a single line.
Try for clarity of concept rather than fewest characters; Reduce prototypical lookup to an absolute minimum.
Create no variables nor use any flow control structures i.e. no loops.
No Asynchrony (?!)
No unnecessary semicolons (just because)

Once you have a solution that works, make sure you can explain exactly why it works, and why your previous solutions didn't work.
Hint


https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Function/prototype
There's also a particularly elegant solution that uses an API introduced in ES2015.

Please don't post answers here (or in reply to the original tweet)

Do feel free to tweet them at me https://twitter.com/secoif

  
## foreach-fn-call.js
// the array of functions
const fns = [
  function () {
    console.log(1)
  },
  function () {
    console.log(2)
  },
  function () {
    console.log(3)
  }
]

const call = // ??? your implementation here. Do not use the `function` keyword or arrow functions.

fns.forEach(call) // change this line if you like

// Expected console output should be
// 1
// 2
// 3
	// the array of functions
	const fns = [
	function () {
	console.log(1)
	},
	function () {
	console.log(2)
	},
	function () {
	console.log(3)
	}
	]

	const call = // ??? your implementation here. Do not use the `function` keyword or arrow functions.

	fns.forEach(call) // change this line if you like

	// Expected console output should be
	// 1
	// 2
	// 3