Created
April 19, 2023 13:50
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Does the dudel discount work for single-decrement lifetables? Looks like it's not a bad approximation.
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ex = c(84.18, 83.55, 82.58, 81.59, 80.6, 79.61, 78.62, 77.62, | |
76.63, 75.64, 74.64, 73.64, 72.65, 71.66, 70.67, 69.68, 68.7, | |
67.71, 66.72, 65.74, 64.76, 63.78, 62.8, 61.81, 60.83, 59.85, | |
58.88, 57.89, 56.91, 55.94, 54.96, 53.98, 53, 52.03, 51.06, | |
50.08, 49.11, 48.14, 47.17, 46.2, 45.24, 44.27, 43.3, 42.34, | |
41.39, 40.44, 39.48, 38.53, 37.59, 36.65, 35.72, 34.79, 33.87, | |
32.95, 32.03, 31.12, 30.22, 29.32, 28.43, 27.54, 26.66, 25.79, | |
24.92, 24.06, 23.21, 22.37, 21.53, 20.7, 19.88, 19.06, 18.27, | |
17.47, 16.68, 15.92, 15.18, 14.44, 13.71, 12.99, 12.28, 11.59, | |
10.93, 10.29, 9.65, 9.03, 8.44, 7.88, 7.33, 6.81, 6.32, 5.85, | |
5.41, 5.01, 4.64, 4.3, 3.98, 3.68, 3.41, 3.16, 2.93, 2.72, | |
2.53, 2.36, 2.2, 2.07, 1.94, 1.83, 1.74, 1.65, 1.58, 1.53, | |
1.49) | |
lx = c(100000L, 99562L, 99533L, 99521L, 99508L, | |
99497L, 99486L, 99475L, 99469L, 99460L, 99454L, 99448L, 99440L, | |
99433L, 99417L, 99396L, 99376L, 99360L, 99340L, 99313L, 99283L, | |
99254L, 99223L, 99196L, 99164L, 99131L, 99094L, 99063L, 99027L, | |
98989L, 98954L, 98908L, 98868L, 98816L, 98765L, 98721L, 98663L, | |
98603L, 98541L, 98472L, 98399L, 98322L, 98244L, 98154L, 98051L, | |
97932L, 97819L, 97692L, 97550L, 97390L, 97208L, 97016L, 96796L, | |
96560L, 96305L, 96031L, 95733L, 95413L, 95053L, 94664L, 94251L, | |
93791L, 93292L, 92770L, 92186L, 91554L, 90868L, 90161L, 89372L, | |
88519L, 87548L, 86565L, 85490L, 84244L, 82873L, 81432L, 79889L, | |
78230L, 76437L, 74459L, 72239L, 69883L, 67372L, 64685L, 61697L, | |
58479L, 55106L, 51492L, 47669L, 43668L, 39533L, 35221L, 30925L, | |
26679L, 22607L, 18842L, 15340L, 12197L, 9453L, 7128L, 5220L, | |
3705L, 2546L, 1691L, 1084L, 671L, 400L, 230L, 127L, 68L, 35L) | |
lx <- lx/1e5 | |
dx <- -diff(c(lx,0)) | |
qx <- dx / lx | |
px <- 1 - qx | |
lt1 <-cbind(rbind(0,diag(px)),0) | |
I <- diag(length(px)+1) | |
plot(colSums(solve(I - lt1))[1:length(ex)] - ex) | |
plot(colSums(solve(I - lt1))[1:length(ex)] - .5 - ex) |
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