判断傻密码的函数

stupid_password.py

def is_stupid_password(password):
    '''look here http://coolshell.cn/articles/6193.html .'''
    stupid_password_list = [
        '123456789',
        '12345678',
        'dearbook',
        '123123123',
        '1234567890',
        '147258369',
        '987654321',
    ]
    clean = list(set(password)) # 如果是 aaaaaaa这样的密码，就会返回['a']
    if password in stupid_password_list or len(clean) is 1:
        return True
    else: return False