Returning multiple values with pointers

References.cpp

#include "stdafx.h"
#include <iostream>
using namespace std;

void FreezeWindow();

void FreezeWindow() {
	char response;
	cin >> response;
}

short Factor(int n, int* pSquared, int* pCubed);

int main() {
	int number, squared, cubed;
	short error;

	cout << "Enter a number (0-20); ";
	cin >> number;

	error = Factor(number, &squared, &cubed);

	if (!error) {
		cout << "number: " << number << endl;
		cout << "square: " << squared << endl;
		cout << "cubed: " << cubed << endl;
	}
	else {
		cout << "Error encountered" << endl;
		
	}

	FreezeWindow();

	return 0;
}

short Factor(int n, int *pSquared, int *pCubed) {
	short Value = 0;
	// set value to 1, dont change square or cube values
	if (n > 20) {
		Value = 1;
	}else {
		// if n is 3
		// Change square, and cube values, set value to 0
		*pSquared = n*n; // 9 
		*pCubed = n*n*n; // 27
		Value = 0;
	}

	return Value;
}

// output is 
/*****
Enter a number (0 - 20):  3
number: 3
square: 9
cubed: 27

The actual values square, cube, and number are not returned
by using the return mechanism, but are returned by changing
the pointers that were passed into the function.