Simple 2D array with pointers

1Simple2DArrayWithPointers.cpp

#include <iostream>
#include <iomanip>
#include <string>

using std::cout;
using std::cin;
using std::endl;

int main() {

	// We want an array of pointers
	// Start with simple dynamic array

//	int* arr = new int[5];

	// This is an array of int
	// We want array of pointers

	int** arr = new int*[5];

	// This is an array of pointers
	// int** arr means arr is a pointer to a pointer
	// arr is the first element of the array and it points to a pointer

	// Now we want to assign arrays to each of the cells in the array
	// Let's start with the first one

//	arr[0] = new int[10];

	// In arr[0] we have a pointer. That pointer has been initialized to
	// an array or 10 elements.
	// We can repeat the same process in a loop to initialize all "rows"

	/*// Moved below to inside the loop
	for (int i = 0; i < 5; ++i) {
		arr[i] = new int[10]; // Initialize all pointers to a new array of 10 elements
	}*/

	// Now let's point these pointers to some values
	for (int i = 0; i < 5; ++i) {
		arr[i] = new int[10]; // Allocate memory (step on line 35)
		for (int j = 0; j < 10; ++j) {
			arr[i][j] = 10; // Initialize with value
		}
	}

	// Print out these values to see
	for (int k = 0; k < 5; ++k) {
		for (int i = 0; i < 10; ++i) {
			if(i == 9)
			{
				cout << arr[k][i] << endl;
			}
			else
			{
				cout << arr[k][i] << " ";
			}

		}
	}

	// We have to deallocate this memory as well
	// Look for all the new

	// deallocate all the arrays in each cell (the "rows")
	for (int l = 0; l < 5; ++l) {
		delete[] arr[l];
	}
	
	// deallocate the array of pointers
	delete[] arr;
	return 0;
}