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January 24, 2017 21:36
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AddComplexities
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//Sums from 1 to n and then from 1 to m^2 | |
public static long example1(int n, int m) | |
{ | |
long sum = 0; | |
//O(n) | |
for(int i = 1; i <= n; i++;) { | |
sum += i; | |
} | |
//O(m^2) | |
for(int i = 1; i <= m * m; i++ { | |
sum += i; | |
} | |
//Complexity is O(m^2 + n) = O(m^2 + n) | |
return sum; | |
} | |
// Determines if an array has unique elements. | |
public static boolean example2(int[] array) | |
{ | |
boolean containsUniqueElements = true; | |
// Sort the elements -> O(n lg n) | |
Arrays.sort(array); | |
// Loop through and look at elements O(n) | |
for(int i = 0; i < array.length; i++) { | |
if(array[i] == array[i + i]) containsUniqueElements = false; | |
} | |
// O(n * lg n + n) = O(n * lg n) | |
return containsUniqueElements; | |
} |
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