A Function that removes duplicate values from a sorted Array

removeduplicate.js

const removeDuplicates = (sortedArray) => {
    const filteredArray = [];
    sortedArray.forEach((num)=> {
        if(!filteredArray.includes(num)) {
            filteredArray.push(num);
        }
    });

    return filteredArray.length;
}

Hello @tobi-bams, thank you for participating in Week 1 of Algorithm Fridays.

Your solution works and passes most of the test cases. The only assumption you have made is that the input array cannot have a null value because if I pass a null value to your function, it would break on line 3.

Ideally, you always want to write code that is robust and takes care of edge cases and unexpected input. Basically adding a check to see if sortedArray is not null in your removeDuplicates function, something like if (!sortedArray) return 0.

Also, is there a way we could have solved this problem without having to create another array like you did on line 2? What do you think?

I have posted my solution here, please let me know what you think.

Thank you so much @meekg33k, i really appreciate the feedback.
I have gone through the solutions and have seen what i could have done better.

I hope to do better this week and make sure i consider edge cases when writing code.

I really appreciate and thanks for organizing this.