Get user choice from an enumerated iterable, with pagination of options.

input_paginated_iterable.py

def input_iterable_paginated(msg: str, iterable: object, page_length: int = 5,
                             more: str = "m"):
    """List numbered items from any iterable to be chosen by user input."""
    def get_input(valid: list):
        value = input().strip().lower()
        try:
            value = int(value)
            if value - 1 in range(len(valid)):
                return valid[value - 1]
            else:
                print(f"Invalid input: {value}")
                return get_input(valid)
        except (ValueError, TypeError):
            if value == more:
                return value
            else:
                print(f"Invalid input: {value}")
                return get_input(valid)

    if not page_length:
        page_length = len(iterable)

    # Calculate maximum string width of largest number in options:
    max_width = len(str(len(iterable)))

    print(msg)
    if page_length < len(iterable):
        print(f"(Enter `{more}` to see more available options.)")

    paginate_from, enumerate_from = 0, 1
    choices_displayed = list()
    while True:
        choices = iterable[paginate_from:paginate_from + page_length]
        choices_displayed += choices
        display_options = "\n".join([f"{str(n).rjust(max_width)}: {x}" for n, x in enumerate(choices, enumerate_from)])
        print(display_options)
        user_choice = get_input(valid=choices_displayed)
        if user_choice == more:
            paginate_from += page_length
            enumerate_from += page_length
            if paginate_from >= len(iterable):
                print("No more options to display!")
        else:
            return user_choice