the first argument behaves as expected but the second won't play ball

argument-parsing

###-----------------------------------------------------------------------------
### VARIABLES
###-----------------------------------------------------------------------------
# ENV Stuff
# Reset all variables that might be set
file=

# Variables evaluated as shell arithmetic should be initialized to a default or
# validated beforehand:
verbose=0


###-----------------------------------------------------------------------------
### FUNCTIONS
###-----------------------------------------------------------------------------
# FUNCTION:
show_help()   {
    printf '\n\n%s\n\n' 'Please review this help information and try again.'
}


###-----------------------------------------------------------------------------
### MAIN PROGRAM
###-----------------------------------------------------------------------------
### Parse Arguments
###---
set -x
while :; do
    case "$1" in
        -h|-\?|--help) # Call "show_help" function; display and exit.
            show_help
            exit
            ;;
        --group-name)
                echo "group-name=${2##*=}"
            ;;
        --group-desc)
                echo "group-desc=${4##*=}"
            ;;
        --more-opts)
            ;;  
        -v|--verbose)
            verbose=$((verbose + 1)) # Each -v argument adds 1 to verbosity.
            ;;
        --)              # End of all options.

            shift
            break
            ;;
        -?*)
            printf '\n%s\n' '  WARN: Unknown option (ignored):' "$1" >&2 
            exit
            ;;
        *)               # Default case: If no more options then break out of the loop.
            break
    esac
    shift
done