passwd file parsing

password.rb

# On a system the /etc/passwd has entries with duplicate uids, can you write a python program to print
# the users with duplicate uids.
# User x,y,z duplicate uid 10001 on line 4,7,8
# User x,x duplicate uid 10001 on line 4,10

# This is the initial need to update this

#!/usr/bin/ruby
require 'pp'
z = {}
File.open("passwd","r").each do |line|
  lsp = line.chop.split(":",4)
  z[lsp[0]] ||=0
  z[lsp[2]] ||=0
  z[lsp[0]] = z[lsp[0]] + 1
  z[lsp[2]] = z[lsp[2]] + 1
  end
z.each_key do |m|
  if z[m] >= 2
    puts "#{m} occurred #{z[m]} times"
  end
end